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-16x^2+64x+130=0
a = -16; b = 64; c = +130;
Δ = b2-4ac
Δ = 642-4·(-16)·130
Δ = 12416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12416}=\sqrt{64*194}=\sqrt{64}*\sqrt{194}=8\sqrt{194}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-8\sqrt{194}}{2*-16}=\frac{-64-8\sqrt{194}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+8\sqrt{194}}{2*-16}=\frac{-64+8\sqrt{194}}{-32} $
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